1 Introduction

# Enumerative Aspects of Nullstellensatz Certificates

## Abstract.

Using polynomial equations to model combinatorial problems has been a popular tool both in computational combinatorics as well as an approach to proving new theorems. In this paper, we look at several combinatorics problems modeled by systems of polynomial equations satisfying special properties. If the equations are infeasible, Hilbert’s Nullstellensatz gives a certificate of this fact. These certificates have been studied and exhibit combinatorial meaning. In this paper, we generalize some known results and show that the Nullstellensatz certificate can be viewed as enumerating combinatorial structures. As such, Gröbner basis algorithms for solving these decision problems may implicitly be solving the enumeration problem as well.

Korteweg-de Vries Institute for Mathematics, University of Amsterdam, 1098 XG Amsterdam, Netherlands.

Keywords: Hilbert’s Nullstellensatz, Polynomial Method, Enumerative Combinatorics, Algorithmic Combinatorics

## 1. Introduction

Polynomials and combinatorics have a long common history. Early in both the theories of graphs and of matroids, important polynomial invariants were discovered including the chromatic polynomial, the Ising model partition function, and the flow polynomial, many of which are generalized by the Tutte polynomial [29, 30, 5, 26]. The notion of using generating functions is ubiquitous in many areas of combinatorics and many these polynomials can be viewed as such functions. Another general class of polynomials associated to graphs is the partition function of an edge coloring model [9].

On the other hand, polynomials show up not just as graph parameters. Noga Alon famously used polynomial equations to actually prove theorems about graphs using his celebrated “Combinatorial Nullstellensatz” [1]. His approach often involved finding a set of polynomial equations whose solutions corresponded to some combinatorial property of interest and then studying this system.

Modeling a decision problem of finding a combinatorial structure in a graph by asking if a certain system of polynomial equations has a common zero is appealing from a purely computational point of view. This allows these problems to be approached with well-known algebraic algorithms from simple Gaussian elimination to Gröbner basis algorithms [10, 8]. Using polynomial systems to model these problems also seems to work nicely with semi-definite programming methods [17, 19, 18, 27].

This approach was used in [21], where the question of infeasibility was considered. If a set of polynomial equations is infeasible, Hilbert’s Nullstellensatz implies that there is a set of polynomials acting as a certificate for this infeasibility. For any given finite simple graph, a polynomial system whose solutions corresponded to independent sets of size was originally formulated by László Lovász [22], but other articles have studied the problem algebraically [20, 28].

One of the interesting results in [21] was to show that for these particular systems of polynomials, the Nullstellensatz certificate contained a multivariate polynomial with a natural bijection between monomials and independent sets in the graph. As such, the Nullstellensatz certificate can be viewed as an enumeration of the independent sets of a graph. Furthermore, the independence polynomial can quickly be recovered from this certificate. Later, when modeling the set partition problem, a similar enumeration occurred in the Nullstellensatz certificate [24].

This paper is directly inspired by these two results and we look at the different systems of polynomials given in [21] and show that this phenomenon of enumerative Nullstellensatz certificates shows up in all of their examples. We explain this ubiquity in terms of inversion in Artinian rings. One important example considered in [21] was -colorable subgraphs. This problem has also been studied by analyzing polynomial systems in [2, 14, 25, 13]. We generalize the polynomial systems used in [21] to arbitrary graph homomorphisms.

We also consider existence of planar subgraphs, cycles of given length, regular subgraphs, vertex covers, edge covers, and perfect matchings. On the one hand, these results may be viewed negatively as they imply that a certificate for infeasibility contains much more information than necessary to settle a decision problem. There have also been papers on attempting efficient computations of Nullstellensatz certificates ([11, 12]) and we should expect that often this will be very hard. On the other hand, if one wishes to enumerate combinatorial structures, our results imply algorithms built from known algebraic techniques to solve this problem.

One polynomial system that does not fall into the general setting of the other examples is that of perfect matchings. While there is a natural system of equations modeling this problem that does have enumerative Nullstellensatz certificates, there is another system of polynomials generating the same ideal that does not. We spend the latter part of this paper investigating the second set and try to achieve some partial results in explaining what combinatorial information is contained in the Nullstellensatz certificates.

This paper is organized as follows. In Section 2, we review the necessary background on the Nullstellensatz and make our definitions precise. We then present our motivating example, independent sets, and explain how this particular problem serves as a prototype for other interesting problems. In Section 3, we prove a sufficient condition for a Nullstellensatz certificate to enumerate combinatorial structures and give several examples, some of them new and some reformulations of old ones, that satisfy this property. Lastly, in Section 4, we look at a system of polynomials whose solutions are perfect matchings that do not satisfy this sufficient condition and prove some results about the certificates.

## 2. Background

Given a system of polynomials , consider the set

 V(f1,…,fs)={(α1,…,αn)∈Cn|f1(α1,…,αn)=⋯=fs(α1,…,αn)=0}.

We call such a set an variety (by an abuse of language, we use the term even for reducible and non-reduced sets in this paper). In particular, the empty set is a variety and if , we say that the system of polynomials is infeasible.

One version David Hilbert’s famous Nullstellensatz states that a system is infeasible if and only if there exists polynomials such that (cf. [8]). The set of polynomials are called a Nullstellensatz certificate for the infeasibility of the system. The degree of the Nullstellensatz certificate is defined to be . We note that a Nullstellensatz certificate is dependent on the choice of polynomials defining the system. We will revisit this point later. The second observation is that Nullstellensatz certificates aren’t unique. Often the Nullstellensatz certificates of greatest interest are those of minimum degree.

Research into an “effective Nullstellensatz” has yielded general bounds for the degree of a Nullstellensatz certificate of a system of polynomials [4, 15]. As such, the following general algorithm for finding such certificates has been proposed (cf. [11, 12]). Suppose we have a system of equations in variables, . We want to find such that . Let denote the set of monomials of degree in variables.

We summarize the above pseudocode. First guess at the degree of the Nullstellensatz certificate and then consider generic polynomials in variables of said degree. Then the condition can be reformulated as system of linear equations whose solutions give the coefficients each should have.

If the linear system has no solution, the guessed degree is increased. The general degree bounds guarantee that this process will terminate eventually, implicitly finding a valid certificate of minimal degree, provided the initial polynomial system was infeasible. This algorithm is similar to the XL style Gröbner basis algorithms studied in algebraic cryptography [7, 3]. One way to understand the complexity of this algorithm is to look at the Nullstellensatz certificates that get produced for different systems of polynomials. This algorithm is one of the main motivations behind the inquiry into Nullstellensatz certificates.

In this paper, we will consider combinatorial problems modeled by systems of polynomials in . The problems we consider will all come from the theory of finite graphs and all varieties will be zero dimensional.

### 2.1. Motivating Example

Let us give the first example of a polynomial system modeling a graph problem: independent sets. Lovász gave the following set of polynomials for determining if a graph has an independent set of size .

###### Proposition 2.1 ([22]).

Given a graph , every solution of the system of equations

x2i−xi=0, i∈V(G), {i,j}∈E(G),

corresponds to an independent set in of size .

It is not hard to see that the equations in Proposition 2.1 define a zero-dimensional variety whose points are in bijection with independent sets of size . The first equation says that for all . So every vertex is either in a set or not. The second equation says that two adjacent vertices cannot both be in the same set. The last equation says that precisely vertices are in the set.

If this system is infeasible, then the Nullstellensatz certificate has been explicitly worked out [21]. Many of properties of the certificate encodes combinatorial data. For example, one does not need to appeal to general effective Nullstellensatz bounds as the degree of the Nullstellensatz certificate can be taken to be the independent set number of the graph in question. Combining several theorems from that paper, the following is known.

###### Theorem 2.2 ([21]).

Suppose the system of equations in Proposition 2.1 are infeasible. Then the minimum degree Nullstellensatz certificate is unique and has degree equal to , the independence number of . If

 1=A(−m+n∑i=1xi)+∑{i,j}∈E(G)Qijxixj+n∑i=1Pi(x2i−xi),

with certificate polynomials , and , then the degree of this certificate is realized by ; and . Furthermore, if the certificate is of minimum degree, the monomials in with non-zero coefficients can be taken to be precisely those of the form where is an independent set of . Lastly, the polynomials , , and all have positive real coefficients.

So Theorem 2.2 tells us for a minimum degree certificate, the polynomial enumerates all independent sets of . The coefficients of the monomials, however, will not necessarily be one, so it is not precisely the generating function for independents sets. The precise coefficients were worked out in [21]. In the next section, we show that a similar theorem will hold for many other examples of zero-dimensional varieties coming from combinatorics.

## 3. Rephrasing Nullstellensatz certificates as inverses in an Artinian ring

Recall that a ring is called Artinian is it satisfies the descending chain condition on ideals, i.e. for every infinite chain of ideals , there is some such that for all . Equivalently, viewed as a left module over itself, is finite dimensional, meaning it contains finitely many monomials.

Let be a variety in defined by the equations . Although not standard, we do not assume that is reduced or irreducible, which is to say that often the ideal will not be radical or prime. An ideal is radical if . The quotient ring is called the coordinate ring of . It is an elementary fact from algebraic geometry that is zero dimensional if and only if is Artinian. This is true even for non-reduced varieties.

The polynomial systems coming from combinatorics are designed to have a solution if some combinatorial structure exists. In Subsection 2.1, the combinatorial structure of interest was independent sets in a graph. Many of the polynomials systems that show up in examples have a particular set of equations that always play the same role. Given a polynomial system in , we call a subset of the variables for indicator variables if the polynomial system includes the equations for and for some . This was the case for the example in Subsection 2.1.

The indicator variables often directly correspond combinatorial objects, e.g. edges or vertices in a graph. The equations means that object is either in some structure or not. Then the equation says that there must be objects in the structure. The other equations in the polynomial system impose conditions the structure must satisfy.

Now suppose we are given an infeasible polynomial system in , where are indicator variables. Without loss of generality, let for some . Then one way to find a Nullstellensatz certificate for this polynomial system is to find the inverse of in , which we denote , and then express as . The polynomials will be a Nullstellensatz certificate.

Throughout the rest of this section, we consider an infeasible polynomial system in where are indicator variables and for some not equal to zero. We let

 R:=A/⟨f2,…,fs⟩

and be the variety defined by .

###### Lemma 3.1.

The ring is Artinian if and only if for every , the polynomial system has finitely many solutions.

###### Proof.

We look at the variety defined by the equations . Since are indicator variables, the equations are among the equations . Thus any solution to these equations must have every is equal to either zero or one. Thus there are only finitely many such that has a solution as must be less than or equal to . Furthermore, each such polynomial system has finitely many solutions so the system only has finitely many solutions. Thus is zero dimensional and the ring is Artinian. Conversely, if is Artinian, there can be only finitely many solutions to the system and thus only a finite subset of those solutions can also be a solution to the equation . ∎

From here on out, we assume that is Artinian as this will be the case in every example we consider. This is the consequence of the fact that the polynomial systems are designed to have solutions corresponding to some finite combinatorial structure inside of some larger, yet still finite, combinatorial object. In our examples, we are always looking for some graph structure inside a finite graph. The examples we consider also satisfy another property that we shall assume throughout the rest of this section unless otherwise stated.

###### Definition 3.2.

The system of polynomials in indicator variables is called subset closed if

1. There is a solution of the system where and

2. Let and if and 0 else. If there is a solution of the system where , then for all , there is a solution of the system where .

It is very easy to describe the monomials with non-zero coefficients appearing in the inverse of in the ring . We look at the variety defined by the polynomials which consists of finitely many points. Suppose we are given a solution to the system : , and . We can then map this solution to the point . We see that each solution to the system can be associated to a point on the -dimensional hypercube . Let be the subset of which is the image of this mapping.

Given , we can associate to it the monomial . For any , the monomial regarded as a function restricted to is not identically zero as there is a point in where for all in .

###### Lemma 3.3.

If is subset closed, then for , is in the ideal generated by .

###### Proof.

If this were not the case, there would be a point such that . Let be the set . If , we see that and that there is a solution where . So there must be a solution where by the property of being subset closed. This implies that since , and so we have a contradiction.

This means that for , there is some such that in the ring . The exponent may a priori be greater than one as we have not assumed that the ideal is radical. However, we note that for any , for all because the equations for all are among the polynomials . Thus for , in the ring . ∎

We can thus conclude that the monomials in the indicator variables in are in bijection with combinatorial structures satisfying the constraints of the polynomial system. In Proposition 2.1, the ring modulo the first two sets of polynomials gives a ring whose monomials are of the form , where indexes vertices in an independent set of .

###### Lemma 3.4.

Given , there are no polynomial relations of the form for in except for all . Similarly if all .

###### Proof.

We note that because of the polynomials , any monomial can only take the value of zero or one when restricted to . The only set of non-negative real numbers whose sum is zero is the trivial case where all are zero. The proof for the second assertion is the same as the first. ∎

###### Theorem 3.5.

There is a Nullstellensatz certificate for the system such that the non-zero monomials of are precisely the monomials for .

###### Proof.

We look at the Nullstellensatz certificate where in so we can express in . We now analyze what must look like. First of all we note that over , there is a power series expansion

 1−m+t=−1m∑i≥0(tm)i

viewed as a function in . Replacing with , we get a power series in the indicator variables that includes every monomial in these variables with a negative coefficient.

We consider the partial sums

 −1mk∑i=0(tm)i,t=n∑i=1yi

first taken modulo the ideal generated by the polynomials of the form . This gives a sum where the monomials are for whose coefficients are all negative real numbers. We know from Lemma 3.3, that the monomials in can be taken of the form for ; the other monomials can be expressed in terms of . So then those monomials that are equal to zero modulo can be removed, giving us another sum. If there is a relation of the form , we ignore it. Such relations simply mean that there is a non-unique way to represent this sum in . Lastly, these partial sums converge to the inverse of in which is supported on the monomials of the form for , using the assumption that is Artinian. ∎

Theorem 3.5 guarantees the existence of a Nullstellensatz certificate such that every possible combinatorial structure satisfying the constraints of is encoded in a monomial in the indicator variables appearing with non-zero coefficient in . This is precisely the Nullstellensatz certificate found in Theorem 2.2 since any subset of an independent set is again an independent set.

As it so happens, in Theorem 2.2 this Nullstellensatz certificate is also of minimal degree. However, it is not necessarily the case that the certificate given in Theorem 3.5 is minimal.

The most obvious way for minimality to fail is by reducing by the linear relations among the monomials for with both negative and positive coefficients. However, if all such linear relations are homogeneous polynomials, we show these relations cannot reduce the degree of the Nullstellensatz certificate.

###### Definition 3.6.

We say that the ideal has only homogeneous linear relations among the indicator variables if every equation is of the form for and and has the property that not all are positive or all negative and that for all .

###### Lemma 3.7.

Let be a minimal Nullstellensatz certificate for the system , and suppose that only has positive real coefficients. Then after adding homogeneous relations in the indicator variables to the system, there is a minimal degree Nullstellensatz certificate of the form .

###### Proof.

By adding homogeneous relations in the indicator variables, we claim it is impossible to reduce the degree of if it only has positive real coefficients. Let us try to remove the monomials of highest degree in by adding homogeneous linear relations in the indicator variables. We apply the first linear homogeneous relation to see which monomials we can remove. The relations are of the form where the are all monomials of a given degree and all . Thus we can potentially remove some of the monomials of degree in using such relations, but not all of them. This is true not matter how many linear homogeneous relations we apply; there will always be some monomials of highest degree remaining. However, we might be able to reduce the degree of the other , to get a Nullstellensatz certificate such that the degree of this new certificate is less than the degree of the original. ∎

Given the Nullstellensatz certificate guaranteed by Theorem 3.5, we note that must consist entirely of monomials of the form for . If , then must be of degree as is linear. Let denote the set of monomials (in ) of .

We consider the following hypothetical situation where the Nullstellensatz certificate guaranteed by Theorem 3.5 is not of minimal degree. Given a monomial , we have that for some polynomials , although this is not unique. We define

 degR(μ):=max{deg(μi),over all equalities μ=s∑i=2μifi}.

Then the degree of is .

Suppose that the degree of the certificate is and that for every for every . Then define , which has degree .

Now we note that

 f1β′1−1=f1β1+m−1f1(f1β1−1)−1
 =f1β1−f1β1+1+m−1n∑i=1yi(f1β1−1)−1
 =m−1n∑i=1yi(f1β1−1).

However, since every monomial in is of the form for some , we can express this polynomial as where since for every . So we have found a Nullstellensatz certificate with smaller degree.

In the hypothetical situation above, we were able to drop the degree of the Nullstellensatz certificate by increasing the degree of by one. However, this construction can be iterated and it may be that the degree of must be increased several times before the minimal degree certificate is found. This depends on how high the degrees of are. It may also be the case that adding lower degree monomials also lowers the degree of the certificate.

###### Lemma 3.8.

If be the Nullstellensatz certificate guaranteed by Theorem 3.5 and have only linear homogeneous relations in the indicator variables. If , then this is a Nullstellensatz certificate of minimal degree.

###### Proof.

For any Nullstellensatz certificate , we may assume without loss of generality that the monomials of form a subset of those in . Indeed we may use Lemma 3.3 to say that all monomials for must appear in unless there are linear homogeneous relations in the indicator variables. By Lemma 3.7, reducing alone by these relations will not reduce the degree of . However, this implies that and thus that the degree of the Nullstellensatz certificate has degree , which is the degree of the certificate by assumption. So is a Nullstellensatz certificate is of minimal degree. ∎

Lemma 3.8 tells us that the Nullstellensatz certificate given in Theorem 3.5 is naïvely more likely to be of minimal degree when the degrees of are high with respect to the number of variables, implying that the degrees of are low.

###### Proposition 3.9.

Let have only homogeneous linear relations in the indicator variables and be a Nullstellensatz certificate. Let be supported on the monomials for . Then if for all and , satisfies for all , is a minimum degree Nullstellensatz certificate.

In addition, if is a polynomial system entirely in the indicator variables and there are only homogeneous linear relations, then there is a Nullstellensatz certificate of minimal degree of the form , where is the coefficient polynomial guaranteed by Theorem 3.5.

###### Proof.

We know that contains only monomials of the form for and . By assumption and satisfies for all . This implies for all . Then apply Lemma 3.8.

If we restrict our attention to a system only in the indicator variables, all homogeneous linear relations are in the indicator variables. Furthermore, any equation is a homogeneous linear relation in the indicator variables since these are the only variables in the equation. So these too can be ignored. We can then apply Lemma 3.7. ∎

Proposition 3.9 is a generalization of Theorem 2.2 as we can see from Proposition 2.1 that all of the variables are indicator variables.

### 3.1. Some examples with indicator variables

We now reproduce the first theorem from [21]. This theorem establishes several polynomial systems for finding combinatorial properties of graphs and we shall see that all of them (except for one, which we have omitted from the theorem) satisfy the conditions of Theorem 3.5. Afterwards, we shall present a few new examples that also use indicator variables.

###### Theorem 3.10 ([21]).

1. A simple graph with vertices numbered and edges numbered has a planar subgraph with edges if and only if the following system of equations has a solution:

 −m+∑{i,j}∈Ezij=0. for all {i,j}∈E. for k=1,2,3 and every i∈[n]. for k=1,2,3 and {i,j}∈E. for i∈[n], {i,j}∈E, k∈[3]. for i∈[n], {u,v}∈E, u,v≠i. for every {i,j},{u,v}∈E. for every {i,j},{u,v}∈E. for i,j∈[n]. for i,j∈[n]. for {i,j},{u,v}∈E, k∈[3]. for {i,j}∈E, k∈[3].

For :

 sk(∏\lx@stackreli,j∈[n]i

2. A graph with vertices labeled has a -colorable subgraph with edges if and only if the following systems of equations has a solution:

−m+∑{i,j}∈Eyij=0 for {i,j}∈E. for i∈[n]. for {i,j}∈E.

3. Let be a simple graph with maximum vertex degree and vertices labeled . Then has a subgraph with edges and edge-chromatic number if and only if the following system of equations has a solution:

−m+∑{i,j}∈Eyij=0 for {i,j}∈E. for {i,j}∈E.
 si∏\lx@stackrelj,k∈N(i)j

We can also look at the a system of polynomials that ask if there is a subgraph of graph homomorphic to another given graph. This is a generalization of Part 3 of Theorem 3.10 as -colorable subgraphs can be viewed as subgraphs homomorphic to the complete graph on vertices.

###### Proposition 3.11.

Given two simple graphs (with vertices labeled ) and , there is a subgraph of with edges homomorphic to if and only if the following system of equations has a solution:

−m+∑{i,j}∈Eyij=0 for all {i,j}∈E. for all i∈[n]. for all {i,j}∈E.
###### Proof.

The variables are the indicator variables which designate whether or not an edge of is included in the subgraph. The third set of equations says that if at least one of the edges incident to vertex is included in the subgraph, then vertex must map to a vertex . The last set of equations says that if the edge is included in the subgraph, its endpoints must be mapped to the endpoints of an edge in . ∎

We see that all of these systems of equations have indicator variables and that each system has only finitely many solutions. So Lemma 3.1 says that the rings formed by taking a quotient by the ideal generated by all equations not of the form gives an Artinian ring. We also see that a subset of -colorable subgraph is -colorable, a subset of a planar subgraph is planar, and a subgraph of a -edge colorable subgraph is -edge colorable. Lastly, if a subgraph of is homomorphic to , so is any subgraph of by restricting the homomorphism. So all of these systems are subset closed.

###### Corollary 3.12.

If the first system of equations in Theorem 3.10 is infeasible, there is a Nullstellensatz certificate such that the monomials in are monomials in the variables in bijections with the planar subgraphs. If the second system in Theorem 3.10 is infeasible, the same holds example that the monomials are in bijection with the -colorable subgraphs. If the third system in Theorem 3.10 is infeasible, the same holds except that the monomials are in bijection with the -edge colorable subgraphs. Lastly, if the system of equations in Proposition 3.11 is infeasible, the same holds except that the monomials are in bijection with the subgraphs homomorphic to .

###### Proof.

This follows directly from Theorem 3.5 and Theorem 3.10. ∎

None of the examples in Theorem 3.10 satisfy the conditions of Proposition 3.9 as the indicator variables are a proper subset of the variables in the system. The following theorem gives a few examples that only involve indicator variables. While only three of the four following examples satisfies the conditions of Proposition 3.9, we will see that Theorem 3.5 can be useful in understanding minimum degree certificates if we can analyze the equations directly.

###### Definition 3.13.

Given a graph , we say that a subgraph cages a vertex if every edge incident to in is an edge in .

###### Theorem 3.14.

1. A graph with vertices labeled has a regular spanning subgraph with edges if and only if the following system of equations has a solution:

−m+∑{i,j}∈Eyij=0 for all {i,j}∈E. for every i,ℓ∈[n].

Furthermore, if the system is infeasible, there is a minimal degree Nullstellensatz certificate of the form , where is the coefficient polynomial guaranteed in Theorem 3.5.

2. A graph with vertices labeled has a -regular subgraph with edges if and only if the following system of equations has a solution:

−m+∑{i,j}∈Eyij=0 for all {i,j}∈E. for every i∈[n].

Furthermore, if the system is infeasible, if there exists an edge in a maximum -regular subgraph such that for both of its endpoints, there is an edge incident to it that is in no maximum -regular subgraph, then there is a minimal degree Nullstellensatz certificate of the form , where is the coefficient polynomial guaranteed in Theorem 3.5.

3. A graph with vertices labeled has a vertex cover of size if and only if the following system of equations has a solution:

−(n−m)+∑i∈[n]yi=0 for all i∈[n]. for all {i,j}∈E.

Furthermore, if the system is infeasible, there is a Nullstellensatz certificate of minimal degree such the monomials in are in bijection with the independent sets of .

4. A graph with vertices labeled and edges has an edge cover of size if and only if the following system of equations has a solution:

−(e−m)+∑{i,j}∈Eyij=0 for all {i,j}∈E. for all i∈[n].

Furthermore, if the system is infeasible, there is a minimal degree Nullstellensatz certificate such that the monomials of correspond to the subgraphs of that cage no vertex of .

###### Proof.

We first prove Part 1. First we show that a solution to the system imply the existence of a regular spanning subgraph of size . The indicator variables correspond to edges that will either be in a subgraph satisfying the last set of equations or not. The last set of equations say that every pair of vertices must be incident to the same number of edges in the subgraph. The last equations are homogeneous linear equations and so we use Proposition 3.9 to prove that Nullstellensatz certificate guaranteed in Theorem 3.5 is a minimal degree certificate.

Now we move to Part 2. Once again, the indicator variables correspond to edges that will either be in the subgraph or not. The last set of equations say that the number of that every vertex must be incident to edges in the subgraph or 0 edges. The last equations are not homogeneous linear relations. Now suppose that there is an edge that is in a maximum -regular subgraph and and are edges in none.

The polynomial in the certificate given by Theorem 3.5 contains a monomial for every -regular subgraph. At least one of these monomials contains the variable . There are only two linear relations in which appears: and . The former equation involves the variable and the latter the variable . But neither of these variables appear in monomials of maximal degree by assumption. Therefore monomials of maximal degree involving cannot be gotten rid of by the polynomials . So the total degree of cannot be reduced.

Now we prove Part 3. We first consider a different system modeling vertex cover:

−m+∑i∈[n]xi=0 for all i∈[n]. for all {i,j}∈E.

In this system, the indicator variables correspond to vertices that will be either in a vertex cover or not. The last set of equations say that for every edge, at least one of its endpoints must be included the in the vertex cover. However, this system is not subset closed, in fact it is the opposite. If a set is a vertex cover, so is any superset. So for Theorem 3.5 to be applicable, we make the variable change . Plugging this variable change in gives us the equations in the statement in the theorem and is now subset closed. However, it defines an isomorphic ideal. We then note that these equations model independent set on the same graph and use Theorem 2.2.

Lastly, we prove Part 4. Like in Part 3, we first consider the following system:

−m+∑{i,j}∈Exij=0 for all {i,j}∈E. for all i∈[n].

In this system, the indicator variables correspond to edges that are in the edge cover or not. The last equations say that for every vertex, at least one of its incident edges must be in the edge cover. Once again, this system is the opposite of being subset closed: any superset of an edge cover is an edge cover. So once again we make a variable substitution, this time . Plugging in gives us the system in the statement of the theorem. We then use Proposition 3.9, noting there are no linear relations among the indicator variables, and note that those square free monomials that get sent to zero are those divisible by a monomial of the form . If a monomial is not divisible by a monomial of such a form, it corresponds to a subgraph that cages no vertex.

We see from Part 2 of Theorem 3.14 that whether or not a minimal degree Nullstellensatz certificate exists that enumerates all combinatorial structures satisfying the polynomial constraints is sensitive to the input data. We also from the proofs of Parts 3 and 4 how Theorem 3.5 might not be applicable. However, in the case of a superset closed system, it is generally possible to change it to a subset closed system using the change of variables exhibited in the proof of Theorem 3.14.

While the systems of equations for Parts 3 and 4 of Theorem 3.14 are not the most obvious ones, because they can be obtained from a more straightforward system by a linear change of basis, we have the following Corollary.

###### Corollary 3.15.

Part 1. A graph with vertices labeled has a vertex cover of size if and only if the following system of equations has a solution:

−m+∑i∈[n]xi=0 for all i∈[n]. for all {i,j}∈E.

Furthermore, if the system is infeasible, the degree of a minimum degree Nullstellensatz certificate is the independence number of .

Part 2. A graph with vertices labeled and edges has an edge cover of size if and only if the following system of equations has a solution: